Question

what volume of .123 m naoh, in milliliters, contains 25.0 g of naoh? (density of the solution is 1.05 g / ml)

Answer 1

8.46 liters of 0.123 NaOH contains 25.0 grams of NaOH.

Step-by-step explanation:

Molar is defined as Moles/Liter. 0.123 M means there is 0.123 moles of NaOH per 1 liter. We are asked to determine how many milliliters of this concentration NaOH it would take to deliver 25.0 grams of NaOH.

Use the units to guide the calculation.

Remember that: Concentration x Volume = Moles

(0.123 moles/liter)*(V) = moles

We want 25.0 grams of NaOH. Let's convert that to moles using the molar mass of NaOH:

(25.0 grams NaOH)/(24.0 g/mole) = 1.04 moles NaOH.

Now we can write:

(0.123 moles/liter)*(V) = 1.04 moles NaOH

V = (1.04/0.123) Liters

V = 8.46 liters