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Suppose the first sample is of size 15 and has a variance of 8.6. Also suppose the second sample is of size 20 and has a variance of 10.2. What is the pooled estimate for a common population variance?

1 Answer

3 votes

Answer: The pooled estimate for a common population variance is approximately 9.52.

Explanation:

To find the pooled estimate for a common population variance, we can use the formula:

Pooled Variance = [(n1-1) * Var1 + (n2-1) * Var2] / (n1 + n2 - 2)

In this case, the first sample has a size of 15 and a variance of 8.6, while the second sample has a size of 20 and a variance of 10.2.

Using the formula, we can calculate the pooled estimate for the common population variance as follows:

Pooled Variance = [(15-1) * 8.6 + (20-1) * 10.2] / (15 + 20 - 2)

Pooled Variance = (14 * 8.6 + 19 * 10.2) / (33)

Pooled Variance = (120.4 + 193.8) / 33

Pooled Variance = 314.2 / 33

Pooled Variance ≈ 9.52

Therefore, the pooled estimate for a common population variance is approximately 9.52.

I hope this helps :)

answered
User Andrei Nicusan
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