Final answer:
The magnitude of the vector a→ = (4.9 mm) x^ - (0.70 mm) y^ is calculated using the Pythagorean theorem, resulting in approximately 4.969 mm.
Step-by-step explanation:
The vector a→ = (4.9 mm) x^ - (0.70 mm) y^ is a two-dimensional vector with components along the x and y axes. The magnitude of a vector is given by the square root of the sum of the squares of its components. Therefore, the magnitude of this vector can be found using the Pythagorean Theorem: √((4.9 mm)^2 + (-0.70 mm)^2).
When you calculate this, you arrive at approximately 4.969 mm. Thus, the magnitude of the vector a→ = (4.9 mm) x^ - (0.70 mm) y^ is 4.969 mm.
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