asked 176k views
4 votes
Calculate Kb for a 0.1 M solution of acetate ion, given that Ka for acetic acid is 1.8 x 10−5. Group of answer choices 8.4 x 10−9 7.4 x 10−8 5.56 x 10−10 4.24 x 10−3 6.4 x 10−6 1.8 x 105 1.34 x 10−3

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User Minaz
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7.4k points

1 Answer

4 votes

Answer:

5.56 x 10^-10

Step-by-step explanation:

The ion product of water, Kw, is given by the equation Kw = Ka * Kb. At 25°C, the value of Kw is 1.0 x 10^-14.

Given that the Ka for acetic acid is 1.8 x 10^-5, we can rearrange the equation to solve for Kb:

Kb = Kw / Ka

Substituting the given values:

Kb = (1.0 x 10^-14) / (1.8 x 10^-5)

This gives us a Kb value of approximately 5.56 x 10^-10.

answered
User Nadeem Siddique
by
7.9k points
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