asked 82.0k views
5 votes
How many atoms of copper (Cu) are present in a 35.4g sample of the substance, knowing that Avogadro's number is 6.02×10^23 atoms/mol, and the molar mass (MM) of copper is 63.5g/mol?

asked
User Tanvi B
by
7.4k points

1 Answer

4 votes

Final answer:

A 35.4g sample of copper contains approximately 4.74 x 10^22 atoms of copper.

Step-by-step explanation:

A 35.4g sample of copper contains approximately 4.74 x 1022 atoms of copper. To calculate this, you can use the formula:

Number of atoms = (sample mass / molar mass) x Avogadro's number

Substituting the given values:

Number of atoms = (35.4g / 63.5g/mol) x 6.02 x 1023 atoms/mol = 4.74 x 1022 Cu atoms

answered
User Lkarsten
by
7.8k points
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