Question

How many mgs of calcium would 250g of dry mopane caterpillars provide?

Answer 1

To find the mass of calcium chloride in a solution, you calculate the number of moles using molarity and volume and then multiply by the molar mass. In this case, 250 mL of a 0.200-M solution of calcium chloride contains 5.549 grams of CaCl₂.

Step-by-step explanation:

To determine the mass of calcium chloride in the solution, we need to use the molarity formula, which relates moles of solute to liters of solution. In this case, we are given the molarity (0.200 M) and the volume of the solution (250 mL, which is 0.250 L). First, we calculate the number of moles of CaCl₂ in the solution as follows:

Number of moles = Molarity × Volume = 0.200 mol/L × 0.250 L = 0.050 mol

Next, we use the molar mass of CaCl₂ (110.98 g/mol) to find the mass in grams:

Mass of CaCl₂ = Number of moles × Molar mass = 0.050 mol × 110.98 g/mol = 5.549 g

Therefore, there are 5.549 grams of calcium chloride in 250 mL of a 0.200-M calcium chloride solution.

Answer 2

To find the calcium content in mopane caterpillars, specific nutritional data is needed, which is not provided. The example calculation for calcium chloride shows how to calculate the mass of a chemical in a solution, yielding 5.549 grams of CaCl₂ in 250 mL of a 0.200 M solution.

Step-by-step explanation:

The question of how many milligrams (mg) of calcium 250 grams of dry mopane caterpillars would provide relates to a nutrition analysis of a unique food resource. To answer this, we would need specific data on the calcium content of mopane caterpillars, which is not provided. However, for a similar determination of calcium content, let's use a chemistry question as an example: "How many grams of CaCl₂ (110.98 g/mol) are contained in 250.0 mL of a 0.200-M solution of calcium chloride?" To solve this, you would use the molarity formula, which is moles of solute divided by liters of solution (M = moles/L).

To calculate the moles of CaCl₂, you would multiply the molarity (0.200 mol/L) by the volume in liters (0.250 L). This gives you 0.050 moles of CaCl₂. Then, to find the mass of CaCl₂, multiply the moles by the molar mass (110.98 g/mol).

Calculation:

• Moles of CaCl₂ = 0.200 mol/L x 0.250 L = 0.050 mol
• Mass of CaCl₂ = 0.050 mol x 110.98 g/mol = 5.549 g

In summary, there would be 5.549 grams of CaCl₂ in 250 mL of a 0.200 M solution.