Question

What mass of a 29.0y mass glucose, C6H12O6, solution contains 60.0 g of glucose? A) 200 g B) 150 g C) 100 g D) 50 g

Answer 1

To find the mass of the 29.0y mass glucose solution, we calculate the moles of glucose using its molar mass and convert it to the mass of the solution using the molar ratio.

Step-by-step explanation:

To determine the mass of the glucose solution, we need to calculate the molar mass of glucose and use it to convert the given mass of glucose to moles. Then, we can use the molar ratio of glucose to solution to find the mass of the solution.

1. The molar mass of glucose (C6H12O6) is 180 g/mol.
2. Calculate the moles of glucose by dividing the given mass of glucose (60.0 g) by its molar mass:

• Moles of glucose = 60.0 g / 180 g/mol = 0.333 mol

Use the molar ratio of glucose to solution to find the mass of the solution:

• 1 mol glucose : 29.0 y mass solution
• 0.333 mol glucose : x mass solution

Convert the moles of glucose to mass of the solution:

• x = 0.333 mol * (29.0 y mass solution / 1 mol glucose) = 9.637 y mass solution

Therefore, the mass of the 29.0y mass glucose solution containing 60.0 g of glucose is approximately 9.637 g.

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