The ionic equation for the reaction of aqueous propanoic acid (CH3CH2COOH) with aqueous potassium hydroxide (KOH) can be written as follows:
CH3CH2COOH + OH- → CH3CH2COO- + H2O
In this equation, propanoic acid (CH3CH2COOH) reacts with hydroxide ions (OH-) from potassium hydroxide (KOH) to form the propanoate ion (CH3CH2COO-) and water (H2O).