\To find the value of log 0.125, we can use the property of logarithms that states:
log(base a) (x^y) = y * log(base a) (x)
In this case, we want to find log 0.125, which is equivalent to log(base 10) (0.125).
Since log 2 = 0.3010, we can rewrite 0.125 as 2^(-3).
Using the property of logarithms mentioned earlier, we have:
log(base 10) (0.125) = -3 * log(base 10) (2)
Substituting the given value of log 2 = 0.3010, we get:
log(base 10) (0.125) = -3 * 0.3010
Simplifying the equation:
log(base 10) (0.125) = -0.9030
Therefore, log 0.125 is approximately equal to -0.9030.