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The perimeter of a basketball court is 288 feet, and the width is 50 feet. What is the length?

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Final answer:

To calculate the length of the basketball court with a perimeter of 288 feet and a width of 50 feet, use the perimeter formula P=2l+2w, and solve for the length, which is found to be 94 feet.

Step-by-step explanation:

The perimeter of a basketball court is 288 feet, and the width is 50 feet. To find the length, we use the formula for the perimeter of a rectangle which is P = 2l + 2w, where P stands for perimeter, l stands for length, and w stands for width. Since the perimeter is 288 feet and the width (w) is 50 feet, we can set up the equation: 288 = 2l + 2(50).

First, let's find the total length contribution to the perimeter by subtracting the width contribution from the total perimeter: 288 - 2(50) = 288 - 100 = 188 feet. Next, divide this result by 2 to find the length: 188 � 2 = 94 feet. The length of the basketball court is therefore 94 feet.

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User Jordi Bruin
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