Question

1: An isosceles triangle XYZ has an equal side XY and XZ of length 16 cm. Of the third side YZ is 20 cm, calculate the altitude the triangle Leave Answer in surd form

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Answer 1

2√39 cm

Explanation:

ΔXYZ is an isosceles triangle & XY = XZ, therefore:

YX' = X'Z

= 20 ÷ 2

= 10 cm

ΔXYZ' is a right triangle, therefore:

XY² = YX'² + XX'²

16² = 10² + XX'²

XX'² = 256 - 100

XX' = √156

= 2√39 cm