The molar concentration of Cl⁻ in the unknown solution is approximately 2.81 x 10⁻¹⁰ M.
How to find molar concentration?
The Nernst equation relates the potential of a cell to the standard potential, concentration of reactants and products, and temperature. For this system, the equation is:
E = E° - (RT/nF) ln([Cl⁻]/[AgCl])
where:
E = cell potential (0.0530 V)
E° = standard reduction potential (0.2223 V)
R = gas constant (8.314 J/mol·K)
T = temperature (assumed to be 298 K)
n = number of electrons transferred (1)
F = Faraday constant (96485 C/mol)
[Cl⁻] = molar concentration of Cl- in the unknown solution
[AgCl] = concentration of AgCl
Rearrange the equation to isolate [Cl⁻]:
ln([Cl-]/[AgCl]) = (E° - E) / (RT/nF)
Plug in the known values:
ln([Cl-]/[AgCl]) = (0.2223 V - 0.0530 V) / ((8.314 J/mol·K × 298 K) / (1 × 96485 C/mol))
Simplify and solve for [Cl⁻]:
ln([Cl⁻]/[AgCl]) ≈ -0.0675
[Cl⁻]/[AgCl] = exp(-0.0675)
≈ 0.937
Since [AgCl] is assumed constant, [Cl⁻] ≈ 0.937 × [AgCl].
The solubility product (Ksp) of AgCl is 2.8 x 10⁻¹⁰. Assuming ideal behavior, the concentration of AgCl can be approximated by:
[Ag⁺] × [Cl⁻] = Ksp
Since AgCl is saturated in both solutions, assume [Ag⁺] is the same in both electrodes. Therefore:
[Ag⁺] × [Cl⁻] ≈ 2.8 x 10⁻¹⁰
[Cl⁻] ≈ 2.8 x 10⁻¹⁰ / [Ag+]
Substitute this expression for [Cl⁻] in the previous equation:
0.937 × ([2.8 x 10⁻¹⁰] / [Ag⁺]) ≈ [Cl⁻]
[Ag⁺] ≈ 3 x 10⁻¹⁰
Finally, calculate the concentration of Cl⁻ in the unknown solution:
[Cl⁻] ≈ 0.937 × 3 x 10⁻¹⁰
≈ 2.81 x 10⁻¹⁰ M
Therefore, the molar concentration of Cl⁻ in the unknown solution is approximately 2.81 x 10⁻¹⁰ M.