Explanation:
In triangle ABC, we have DE as one of the legs of the right triangle, and AB as the hypotenuse. We need to find DC, .which is the other leg
Using the Pythagorean theorem, we :can set up the following equation
DE
^2 + DC^2 = AB^2
:Plugging in the given values, we have
DC^2= 36^2 + 2^24
:Simplifying the equation
DC^2 = 1296 + 576
Subtracting 576 from both sides
DC^2 = 1296 - 576
DC^2 = 720
To find the value of DC, we take the :square root of both sides
DC = √720
:Plugging in the given values, we have
DC^2 = 36^2 + 2^24
:Simplifying the equation
DC^2 = 1296 + 576
:Subtracting 576 from both sides
DC^2 = 1296-576
DC^2 = 720
To find the value of DC, we take the :square root of both sides
DC = √720
:Simplifying the square root
DC = 26.87
Therefore, the approximate value of
.DC is 26.87