Question

Two ropes are attached to this lifting eye. Force A is 1200N at 75°, and Force B is 1600N at 60° from horizontal. What is the RESULTANT of these two forces?"

Answer 1

To find the resultant of the two forces, break each force into its horizontal and vertical components. Add up the horizontal and vertical components separately, then use the Pythagorean theorem and trigonometry to find the magnitude and angle of the resultant.

Step-by-step explanation:

To find the resultant of the two forces, we need to break each force into its horizontal and vertical components. For Force A, the horizontal component is 1200N * cos(75°) and the vertical component is 1200N * sin(75°). For Force B, the horizontal component is 1600N * cos(60°) and the vertical component is 1600N * sin(60°). Once we have the horizontal and vertical components for both forces, we can add them up to find the resultant.

The horizontal components are: Force A = 1200N * cos(75°) and Force B = 1600N * cos(60°). Adding them up, we get: (1200N * cos(75°)) + (1600N * cos(60°)).

The vertical components are: Force A = 1200N * sin(75°) and Force B = 1600N * sin(60°). Adding them up, we get: (1200N * sin(75°)) + (1600N * sin(60°)).

Finally, we can use the Pythagorean theorem to find the magnitude of the resultant, and trigonometry to find its angle with respect to the horizontal.

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