Answer:
Explanation:
To find the velocity of the ball as it left the table, we can use the principles of projectile motion and energy conservation.
1. First, we need to find the time it takes for the ball to fall from the table to the floor. We can use the equation for vertical motion:
h = (1/2) * g * t^2
where h is the vertical distance (1.2m), g is the acceleration due to gravity (9.8 m/s^2), and t is the time.
Rearranging the equation to solve for t, we have:
t = sqrt(2h / g)
Substituting the values, we get:
t = sqrt(2 * 1.2 / 9.8) = 0.49 s (rounded to two decimal places)
2. Next, we can calculate the horizontal velocity of the ball using the equation:
velocity = distance / time
Given that the horizontal distance is 2m and the time is 0.49s, we have:
velocity = 2 / 0.49 ≈ 4.08 m/s (rounded to two decimal places)
Therefore, the velocity of the ball as it left the table is approximately 4.08 m/s.