Answer:
7.534 × 10^24 atoms of Fe
12.524 moles of Fe in 700.0 g of iron.
Step-by-step explanation:
To determine the number of Fe atoms and the amount (moles) of Fe atoms in 700.0 g of iron, we need to use the molar mass of iron.
The molar mass of iron (Fe) is 55.845 g/mol.
First, we can calculate the number of moles of Fe in 700.0 g of iron by using the formula:
moles = mass (g) / molar mass (g/mol)
moles of Fe = 700.0 g / 55.845 g/mol
moles of Fe ≈ 12.524 mol
To find the number of Fe atoms, we can use Avogadro's number, which states that there are 6.022 × 10^23 atoms in one mole of any substance.
number of Fe atoms = moles of Fe × Avogadro's number
number of Fe atoms = 12.524 mol × 6.022 × 10^23 atoms/mol
number of Fe atoms ≈ 7.534 × 10^24 atoms
In conclusion, there are approximately 7.534 × 10^24 atoms of Fe and 12.524 moles of Fe in 700.0 g of iron.