Question

There are always 4 bars of chocolates,left when box of chocolates sharedequally among 8, 10, or 12 children.Find the smallest number of chocolatesin the box,

Answer 1

8 = 2 × 2 × 2

10 = 2 × 5

12 = 2 × 2 × 3

LCM = 2 × 2 × 2 × 3 × 5 = 120

120 + 4 = 124

The smallest number of chocolates in the box is 124.