Question

Find the perimeter of the triangle with vertices. Round your answer to the nearest tenth. A(-2, 5) B(3, 8) C(7, -4)

Answer 1

perimeter = √34 + √160 + √162

perimeter ≈ 31.21

Explanation:

AB = √[(3 + 2)² + (8 - 5)²] = √34

BC = √[(7 - 3)² + (-4 - 8)²] = √160

AC = √[(7 + 2)² + (-4 - 5)²] = √162

perimeter = √34 + √160 + √162

perimeter ≈ 31.21