The correct option is:
Option 3: Tertiary (3°)
To classify the second carbon of 2,2-dimethylbutane, we should look at the number of carbon-containing groups attached to it. Here are the steps to determine the classification:
1. Identify the Carbon in Question: First, we need to locate the second carbon in the chain of 2,2-dimethylbutane. In organic chemistry, carbons are numbered starting from the end closest to a substituent. The prefix "2,2-" tells us that there are substituents on the second carbon atom.
2. Count the Carbon-Containing Groups Attached: We then count the number of carbon-containing groups (alkyl groups or carbon atoms) that are directly attached to the second carbon atom.
3. Classify the Carbon: The classification is based on this count:
- Primary (1°): A carbon atom bonded to only one other carbon atom.
- Secondary (2°): A carbon atom bonded to two other carbon atoms.
- Tertiary (3°): A carbon atom bonded to three other carbon atoms.
- Quaternary (4°): A carbon atom bonded to four other carbon atoms.
For 2,2-dimethylbutane, the second carbon is the one with the two methyl groups attached to it. This means it is bonded to three other carbon atoms: the two methyl groups and the carbon atom that continues the main chain. Therefore, it is classified as a tertiary (3°) carbon.