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suppose the world's population increased exponentially from 4.454 billion in 1980 to 5.931 billion in 1998 and continued to increase at the same percentage rate between 1998 and 2008. (a) Find an equation of the form P = P₀aᵗ, where P is the world's population in billions and t is the number of years since 1980.

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User Webby
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1 Answer

3 votes

Answer:

To find the equation of the form P = P₀aᵗ, we need to determine the values of P₀ and a.

Given that the population was 4.454 billion in 1980 (t = 0) and 5.931 billion in 1998 (t = 18), we can use these data points to find the values of P₀ and a.

Using the formula P = P₀aᵗ, we can set up two equations:

4.454 = P₀a⁰

5.931 = P₀a¹⁸

Since a⁰ is equal to 1, the first equation simplifies to:

4.454 = P₀

Substituting this value into the second equation, we have:

5.931 = 4.454a¹⁸

To solve for a, we can divide both sides of the equation by 4.454 and then take the 18th root:

a = (5.931 / 4.454)^(1/18)

Simplifying this expression, we find:

a ≈ 1.014

Therefore, the equation of the form P = P₀aᵗ, representing the world's population, is:

P = 4.454 * (1.014)^t

Explanation:

Let's break it down step by step:

1. We have two data points: the population in 1980 (4.454 billion) and the population in 1998 (5.931 billion).

2. We want to find the equation of the form P = P₀aᵗ, where P is the population in billions and t is the number of years since 1980.

3. Using the first data point, we know that when t = 0 (1980), the population is P₀. So, P₀ = 4.454 billion.

4. Using the second data point, we can substitute the values into the equation and solve for a: 5.931 = 4.454a¹⁸.

5. To solve for a, we divide both sides of the equation by 4.454 and then take the 18th root: a = (5.931 / 4.454)^(1/18).

6. Simplifying the expression, we find that a is approximately equal to 1.014.

7. Therefore, the equation of the form P = P₀aᵗ representing the world's population is: P = 4.454 * (1.014)^t.

I hope this helps! Let me know if you have any other questions.

answered
User MJ X
by
7.5k points
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