Question

Write the equation of a line that passes through the point (8, 9), and is

perpendicular to y=6-4x.

Answer 1

y = (1/4)x + 7

Explanation:

y = 6 - 4x

y = -4x + 6

y = mx + b

m = -4

The slope of the given line is -4.

The slope of the perpendicular is 1/4.

y = mx + b

y = (1/4)x + b

9 = (1/4)(8) + b

9 = 2 + b

b = 7

y = (1/4)x + 7