Answer:
Step-by-step explanation: . Identify the multiples of 2: Start from 102 (the first multiple of 2 greater than 100) and increment by 2 until reaching 198 (the last multiple of 2 less than 200). We get 102, 104, 106, ..., 196, 198.
2. Identify the multiples of 3: Start from 102 (the first multiple of 3 greater than 100) and increment by 3 until reaching 198 (the last multiple of 3 less than 200). We get 102, 105, 108, ..., 195, 198.
3. Combine the two sets of multiples and remove any duplicates. We obtain the following sequence: 102, 104, 105, 106, 108, ..., 195, 196, 198.
4. Calculate the sum of the sequence using the formula for the sum of an arithmetic series. The formula is Sn = (n/2)(a + l), where Sn is the sum, n is the number of terms, a is the first term, and l is the last term. In this case, a = 102, l = 198, and n = (198 - 102) / 2 + 1 = 49.
5. Substitute the values into the formula: Sn = (49/2)(102 + 198) = (49/2)(300) = 7350.
Therefore, the sum of all multiples of 2 or 3 between 100 and 200 (excluding 100 and 200) is 7350.