Let’s denote the three numbers as a, b, and c. According to the problem, we have the following equations:
a + b + c = 96 (The sum of three numbers is 96)
c = 3b (The third number is thrice the second number)
b = a + 4 (The second number is four more than the first)
We can substitute equations 2) and 3) into equation 1):
a + (a + 4) + 3(a + 4) = 96 5a + 16 = 96 5a = 80 a = 16
Substitute a = 16 into equation 3) to find b:
b = a + 4 = 16 + 4 = 20
Substitute b = 20 into equation 2) to find c:
c = 3b = 3*20 = 60
So, the three numbers are 16, 20, and 60.