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The x-component of vector A is -25.0 m and the y-component is +40.0 m. What is the angle between the direction of vector A and the positive direction of vector x?

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User HAK
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1 Answer

6 votes

The angle θ between the direction of vector A and the positive direction of x can be found using the tangent of the angle θ, which is the ratio of the y-component to the x-component of the vector.

The formula to find the angle is:

θ = atan(|Ay/Ax|)

where Ay and Ax are the y and x components of vector A, respectively.

Substituting the given values:

θ = atan(|40.0/-25.0|)

This gives us θ = atan(1.6).

However, because the x-component is negative and the y-component is positive, this means that the vector is in the second quadrant. The arctangent function typically returns values in the range (-π/2, π/2), which corresponds to the first and fourth quadrants, so we need to add π/2 (or 90 degrees) to get the angle in the correct quadrant.

So, θ = atan(1.6) + π/2.

Using a calculator to find the arctangent and converting from radians to degrees (since 1 radian is approximately 57.3 degrees), we get:

θ ≈ 58 degrees + 90 degrees = **148 degrees**.

So, the angle between the direction of vector A and the positive direction of x is **148 degrees**.

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User Scrashdemix
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