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(x+3)² +(y−1)² =121 The graph of the equation above in the xy-plane is a circle. What is one possible value of x ?

1 Answer

5 votes

Answer:

8

Explanation:

By comparing the given equation to the standard form of a circle equation, (x - h)² + (y - k)² = r², we can see that the center of the circle is (-3, 1) and the radius is √121, which simplifies to 11.

To find one possible value of x, we can use the center of the circle (-3, 1) as a reference point. Since the x-coordinate of the center is -3, any x-value that is 11 units to the left or right of -3 will lie on the circle.

One possible value of x is 8, which is 11 units to the right of -3. Therefore, x = 8 is one possible value that satisfies the equation and lies on the graph of the circle in the xy-plane.

answered
User Ravash Jalil
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