Question

How many milliliters of a stock solution of 10.0 M HNO₃ would you have to use to prepare 0.450 L of 0.500 M HNO₃?

Answer 1

`\huge{ \boxed{0.023 \: \text{L}}}`

Step-by-step explanation:

The volume of the stock solution required can be found by using the formula:

`C_1V_1 = C_2V_2`

where

C1 is the concentration of the stock solution

V1 is the volume of the stock solution

C2 is the concentration of the final solution

V2 is the volume of the final solution

From the question:

C1 = 10 M

V1 = ?

C2 = 0.5 M

V2 = 0.45 L

Making V1 the subject we have;

`V_1 = (C_2V_2)/(C_1)`

`\therefore \: V_1 = (0.5 * 0.45)/(10) = (0.225)/(10) \\ = 0.0225`

We have the final answer as:

0.023 L