Answer:
Explanation:
Let the four numbers be a, b, c and d where a is multiple of 19 and b, c and d are equal.
a + b + c + d = 93
Since b = c = d, we can say a + b + b + b = 93
a + 3b = 93
Now let’s assume a is 19, then 3b = 93 - 19 = 74
But 74 is not evenly divisible by 3. So a cannot be 19.
Let’s assume a is 38 (next multiple of 19), then 3b = 93 - 38 = 55
But 55 is not evenly divisible by 3. So a cannot be 38.
Let’s assume a is 57 (next multiple of 19), then 3b = 93 - 57 = 36
36 is evenly divisible by 3. So a is 57 and b is 36/3 = 12
Ascending order will be 12, 12, 12, 57
Answer: 12, 12, 12, 57