Question

PLEASE HELP I HAVE TO TURN IT IN NEXT PERIOD

h(a) = 4a
g(a)=2a³ + 2a²-a
Find (h-g)(a)

Answer 1

`(h-g)(a)=-2a^3-2a^2+5a`

Explanation:

Given functions:

`h(a) = 4a`

`g(a)=2a^3 + 2a^2-a`

To determine the composite function (h - g)(a), we can subtract function g(a) from function g(a):

`\begin{aligned}(h-g)(a)&=h(a)-g(a)\\&=4a-(2a^3+2a^2-a)\\&=4a-2a^3-2a^2+a\\&=-2a^3-2a^2+4a+a\\&=-2a^3-2a^2+5a\end{aligned}`