Question

A tennis ball of mass 7.0×10−2 kg and speed 34 m/s strikes a wall at a 45 ∘ angle and rebounds with the same speed at 45 ∘. A tennis ball moves upward and to the right, hits a vertical wall at 45 degrees to its surface, and rebounds at the same angle. After the collision, the ball moves upward and to the left. What is the magnitude of the impulse given to the ball? Express your answer using two significant figures.

Answer 1

3.4 kg m/s

Step-by-step explanation:

Momentum is conserved in the y-direction.

Impulse = change in momentum in the x-direction.

J = p − p₀

J = m (v − v₀)

J = (7.0×10⁻² kg) (34 sin 45° m/s − -34 sin 45° m/s)

J = 3.4 kg m/s