asked 24.1k views
5 votes
P(x) = (x^2 - 16) (2x - 9). What are the real zeros of the polynomial function?

1 Answer

5 votes

Answer:

x² - 16 = 0 or 2x - 9 = 0

x² = 16 or 2x = 9

x = ±4 or x = 4.5

The real zeros are -4, 4, and 4.5.

answered
User Ninjaneer
by
8.2k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.