Final answer:
To calculate the boiling point of a solution, use the equation ΔT = Kbm, where ΔT is the boiling point elevation, Kb is the molal boiling point constant, and m is the molality of the solution. First, calculate the molality of the solution by dividing the moles of solute by the kilograms of solvent. Then, use the molality and molal boiling point constant to find the boiling point elevation. Finally, add the boiling point elevation to the boiling point of pure water to get the boiling point of the solution.
Step-by-step explanation:
To calculate the boiling point of a solution, we can use the equation: ΔT = Kbm, where ΔT is the boiling point elevation, Kb is the molal boiling point constant, and m is the molality of the solution.
First, we need to calculate the molality of the solution. Molality (m) is defined as the moles of solute per kilogram of solvent. In this case, we have 1.04g of glucose, which is equivalent to 0.0058 moles, and 80.2g of water, which is equivalent to 4.46 moles. So, the molality of the solution is 0.0058 mol/4.46 kg = 0.0013 mol/kg.
Next, we can use the molality and molal boiling point constant to calculate the boiling point elevation. Kb for water is given as 0.52K kg mol-1. Plugging in the values, we get ΔT = 0.52K kg mol-1 * 0.0013 mol/kg = 0.0007K.
Finally, to find the boiling point of the solution, we add the boiling point elevation to the boiling point of pure water. The boiling point of pure water = 373.15K. So, the boiling point of the solution is 373.15K + 0.0007K = 373.15K.
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