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One number is 10 more than twice another and the sum is negative eleven​

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Answer:Let’s denote the two numbers as (x) and (y). According to the problem, we have two equations:

(y = 2x + 10): One number is 10 more than twice another.

(x + y = -11): The sum of the two numbers is -11.

We can solve these equations step by step:

Substitute (y) from the first equation into the second equation: (x + 2x + 10 = -11).

Simplify to get (3x + 10 = -11).

Subtract 10 from both sides to get (3x = -21).

Divide both sides by 3 to find (x = -7).

Then substitute (x = -7) into the first equation to find (y):

(y = 2*(-7) + 10 = -14 + 10 = -4).

So, the two numbers are (-7) and (-4). I hope this helps! If you have any more questions, feel free to ask.

Explanation:

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User Burak Karasoy
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