Answer:
(2a + 3)(3a - 5)
Explanation:
given
6a² - a - 15
consider the factors of the product of the coefficient of the a² term and the constant term which sum to give the coefficient of the a- term
product = 6 × - 15 = - 90 ans sum = - 1
the factors are + 9 and - 10
use these factors to split the a- term
= 6a² + 6a - 10a - 15 ( factor the first/second and third/fourth terms )
= 3a(2a + 3) - 5(2a + 3) ← factor out (2a + 3) from each term
= (2a + 3)(3a - 5) ← in factored form