Answer:
E = K M ΔT energy required to heat water
M = 1.5E3 kg = 1.5E6 gm
E = 1 cal / gm C * 1.5E6 gm * 30 C = 4.5E7 cal
1 cal = 4.19 J
E = 4.19 * 4.5E7 J = 1.88E8 J
E(req) = 1.88E8 / .75 J = 2.51E8 J total heat required
1 kWh = 1 * 1000 J hr * 3600 sec / hr = 3.6E6 J
t = E(req) / E (input) = 2.51E8 / 3.6E6 = 69.7 sec
.09 / sec * 69.7 sec = 627 cents = 6.27 $
(Note 1500 kg = 3300 lbs or over 1.5 tons of water)