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Help :) one segment, 10th grade geometry

Help :) one segment, 10th grade geometry-example-1

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Answer:

JL = 6

Explanation:

First, we can solve for x using the segment addition postulate, which states that if point C is on line segment AB, then AC + CB = AB.

For this problem, we can construct the equation:

JK + KL = JL

And we can use this to solve for x by plugging in the given segment lengths:

(5x + 7) + 4 = 2x + 8

↓ subtracting 2x from both sides

3x + 11 = 8

↓ subtracting 11 from both sides

3x = -3

↓ dividing both sides by 3

x = -1

Now, we can solve for JL by plugging the x-value into its given length definition:

JL = 2(-1) + 8

JL = 8 - 2

JL = 6

answered
User Danilo Tommasina
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