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Find the angle of a triangle whose sides are (10x-5)°, (15x+10)°, (25x-5)°.

1 Answer

1 vote

Answer:

m∠1 = 31°

m∠2 = 64°

m∠3 = 85°

Explanation:

We know that all triangle angles add up to 180°, so you can add the 3 angles provided together and equal it to 180.

(10x-5) + (15x+10) + (25x-5) = 180

You can remove the parenthesis, then combine like terms.

10x - 5 + 15x + 10 + 25x - 5 = 180

50x + 0 = 180

50x = 180

Now, you can divide both sides by 50 to find x.

50x ÷ 50 = 180 ÷ 50

x = 3.6

Now, to find each angle, replace x in the angle with 3.6

m∠1 = 10(3.6) - 5

m∠1 = 36 - 5

m∠1 = 31°

m∠2 = 15(3.6) + 10

m∠2 = 54 + 10

m∠2 = 64°

m∠3 = 25(3.6) - 5

m∠3 = 90 - 5

m∠3 = 85°

Hope this helps!

answered
User Gruber
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