Question

When 10 is subtracted from the square of a number, the result is 3 times the number. Find the positive solution

Answer 1

Explanation:

Step 1: Let the number is x

Step 2:
`x^(2)` - 10 = 3x

Step 3: Solve the equation:

`x^(2)` - 3x = 10,

`x^(2)` - 3x - 10 = 0

Step 4: Factor
`x^(2)` -3x -10 using the AC method.

Consider the form
`x^(2)`+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is −10 and whose sum is −3. The numbers are −5 and 2. Write the factored form using these integers.(x−5)(x+2)=0. If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0, x - 5 = 0, x = 5 and x + 2 = 0, x = -2

So the positive solution is 5.

Answer: 5