Question

The following diagram shows a junction with various currents flowing in and out of it. What is the current x? Diagram of current flow in Amperes (A) depicts a small shaded circle in the middle with three arrows labeled 0.2A (bottom), 0.4A (left) and 2A (top left) towards the circle, and two arrows labeled 0.5A (top right) and X (right) away from the circle. A. 2.1 A B. 3.1 A C. –2.1 A D. 0.5 A

Answer 1

To determine the current x in the given junction, you can apply Kirchhoff's current law, which states that the sum of currents entering a junction is equal to the sum of currents leaving the junction.

In this case, you have:

Total current entering = Total current leaving

(0.2 A + 0.4 A + 2 A) = (0.5 A + x)

Now, calculate the total current entering and leaving:

(2.6 A) = (0.5 A + x)

To solve for x, you can rearrange the equation:

x = 2.6 A - 0.5 A

x = 2.1 A

So, the current x is 2.1 A, which corresponds to option A.