asked 130k views
3 votes
Find the perpendicular distance from the point (3, -4) to the line 3x- 4y + 10 =0.​

asked
User Neel
by
8.3k points

1 Answer

2 votes

Answer:

3x - 4y = -10

-4y = -3x - 10

y = (3/4)x + (5/2)

The slope of the perpendicular line will be -4/3.

From (3, -4), go up 4 units, then left 3 units. You will be at (0, 0), so the equation of this line is y = (-4/3)x.

(3/4)x + (5/2) = (-4/3)x

9x + 30 = -16x

25x = -30

x = -6/5, so y = (-4/3)(-6/5) = 24/15 = 8/5

d = √((3 - (-6/5))² + (-4 - (8/5))²)

= √((21/5)² + (-28/5)²)

= (1/5)√(21² + (-28)²)

= (1/5)√(441 + 784)

= (1/5)√1,225

= (1/5)(35)

= 7

answered
User Wraithseeker
by
7.4k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.