The balanced chemical equation for the reaction of liquid enanthic acid (C6H13COOH) with gaseous oxygen (O2) to form gaseous carbon dioxide (CO2) and liquid water (H2O) is as follows:
C6H13COOH(l) + 9.5O2(g) → 6CO2(g) + 7.5H2O(l)
To balance the equation, we need to ensure that the same number of each type of atom is present on both sides of the equation. In this balanced equation, we have:
- 6 carbon (C) atoms on both sides.
- 13 hydrogen (H) atoms on both sides.
- 19 oxygen (O) atoms on both sides.
The equation is balanced. However, it's worth noting that in reality, you can't have a fractional coefficient like 9.5 in front of O2. In such cases, you would typically multiply all coefficients by a suitable factor to convert the fractional coefficient into a whole number while still maintaining the balance. For example, you can multiply all coefficients by 2 to get a balanced equation with whole numbers:
2C6H13COOH(l) + 19O2(g) → 12CO2(g) + 15H2O(l)