Question

3. an electron is accelerated by a constant electric field of magnitude 600. n/c. find: a) force acting on the electron by the electric field; b) the acceleration of the particle by the electric force; c) assuming the electron starts from rest, find its speed after 2.50 ns.

Answer 1

Step-by-step explanation:

Given:

E = 600 N/C

q = 1.6 × 10⁻¹⁹ C

m = 9.1 × 10⁻³¹ kg

v₀ = 0

t = 2.5 ns = 2.5 × 10⁻⁹ s

a)

F = qE

= 1.6 × 10⁻¹⁹ × 600

= 9.6 × 10⁻¹⁷ N

b)

F = ma

9.6 × 10⁻¹⁷ = 9.1 × 10⁻³¹a

a = 9.6 × 10⁻¹⁷ ÷ (9.1 × 10⁻³¹)

= 1.05 × 10¹⁴ m/s

c)

v = v₀ + at

= 0 + 1.05 × 10¹⁴ × 2.5 × 10⁻⁹

= 2.625 × 10⁵ m/s