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a population in hardy-weinberg equilibrium has a gene that has one dominant allele and one recessive allele. the frequency of the dominant allele is 0.3. what is the frequency of the recessive allele?

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User Aximili
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1 Answer

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Answer: 0.7

Explanation: The equations for Hardy-Weinberg Equilibrium are P^2+2Pq+q^2=1 and P+q=1. The first allows calculation of genotypic frequencies while the second allows for allele frequencies. Using the second equation, 0.3 + q=1. Therefore, q =0.7.

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User FnCzar
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