Question

If a yellow pea plant with round seeds that has the genotype GgWw is crossed to itself, what proportion of the offspring will be green with round seeds? a. 3/16 b. 9/16 c. 1/16 d. 0

Answer 1

When the given pea plant with genotype GgWw is self-fertilized, according to Mendelian genetics, only 1/16 of the offspring will have the phenotype of green color and round seeds. The correct option C.

Step-by-step explanation:

In order to answer this question, we need to apply the principles of Mendelian genetics. The genotype GgWw represents a yellow, round-seeded pea plant where G and W stand for yellow and round respectively (dominant traits), and g and w stand for green and wrinkled respectively (recessive traits).

When GgWw is self-fertilized, a Punnett square would show 16 potential outcomes for the offspring. Only one of these 16 would result in a green pea plant with round seeds (gwW-), which represents the genotype and phenotype being asked for in the question.

Thus, the proportion of offspring that will be green with round seeds is 1/16. So, the correct answer is c. 1/16.

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