Question

a box contains 24 electrical components, four of which are defective. if four components are sold at random, find the probability that at least one of the four is defective. give your decimal answer rounded to three decimal places.

Answer 1

HI,

Explanation:

It is therefore a draw without replacement.

Probability for removing 4 non-defective components:

`(20)/(24) *(19)/(23) *(18)/(22) *(17)/(21) =(1615)/(3542) \\`

Probability that at least one of the four is defective:

`1-(1615)/(3542) =(3377)/(3542) =0.9534161490...\approx{0.953}\\`