Question

two cyclists start at the same point and travel in opposite directions. one cyclist travels 3 miles/hour slower than the other. if the two cyclists are 140 miles apart after 4 hours, what is the rate of each cyclist?

Answer 1

Hi,

Explanation:

Let's assume v the rate of the slower cyclist,

v+3 the rate of the faster cyclist,

140=(v+(v+3))*4

2v+3=140/4

2v=35-3

2v=32

v=16 (mi/h :rate of the slower cyclist)

v+3=19 (mi/h :rate of the faster cyclist)