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Write an equation for a line perpendicular to y=-3x+3 and passing through the point (3,-2)

1 Answer

3 votes

Answer:

y = 1/3x -3

Explanation:

You want an equation for the line through (3, -2) that is perpendicular to y = -3x +3.

Slope

The slope of the given line is the coefficient of x: -3.

The slope of the perpendicular line is the opposite reciprocal of this:

-1/(-3) = 1/3

Equation

The point-slope equation of the perpendicular line is ...

y -k = m(x -h) . . . . . . line through (h, k) with slope m

y +2 = 1/3(x -3) . . . . . line through (3, -2) with slope 1/3

Rearranging, we can put this in slope-intercept form:

y = 1/3x -1 -2

y = 1/3x -3 . . . . . equation of the perpendicular line

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Write an equation for a line perpendicular to y=-3x+3 and passing through the point-example-1
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User Wombatp
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