What is the molarity of 750 ml of a solution containing 2.10 moles of Na_2SO_4?

Question

asked Sep 1, 2024 41.5k views

1 Answer

Bleiz · Answer 1 · 2024-09-07T03:43:28+0000

Answer:

$\huge{ \boxed{ 2.8 \: \text{M}}}$

Step-by-step explanation:

The molarity or concentration of
Na_2SO_4 can be found by using the formula;

c = (n)/(v)

c is the concentration in M , mol/dm³ or mol/L

v is the volume in L or dm³

n is the number of moles

From the question;

n = 2.1 moles

v = 750 mL which has to be converted to litres

$1000 \: ml = 1l \\ \therefore \: 750 \: ml = (750)/(1000) * 1l \\ = 0.75 \: l \\ \\ \therefore \: v = 0.75 \: l$

$\therefore \: c = (2.1)/(0.75) = 2.8$

We have the final answer as;