asked 139k views
2 votes
A vector a of magnitude 15 units and another vector b of magnitude 4.6 units differ in directions by 75°. Find (a) the scalar product of

the two vectors and (b) the magnitude of the vector product axb.

asked
User Saleel
by
8.1k points

1 Answer

3 votes

Answer:

a) The scalar product of vectors a and b is 26.01 units.

b) The magnitude of the vector product axb is 64.59 units.

Step-by-step explanation:

To find the scalar product (also known as the dot product) of two vectors a and b, you can use the following formula:

(a · b) = |a| * |b| * cos(θ)

where:

(a · b) represents the dot product of vectors a and b.

|a| is the magnitude (length) of vector a.

|b| is the magnitude (length) of vector b.

θ is the angle between vectors a and b.

In this case, you're given:

|a| = 15 units

|b| = 4.6 units

θ = 75°

Let's calculate the scalar product (a · b):

(a · b) = 15 * 4.6 * cos(75°)

Now, we need to find the value of cos(75°). We can use the trigonometric identity:

cos(75°) = cos(45° + 30°)

Using the sum of angles formula for cosine:

cos(45° + 30°) = cos(45°)cos(30°) - sin(45°)sin(30°)

We know that cos(45°) and sin(45°) are both equal to 1/√2, and cos(30°) and sin(30°) are √3/2 and 1/2, respectively.

cos(75°) = (1/√2) * (√3/2) - (1/√2) * (1/2)

cos(75°) = (√3/2√2) - (1/2√2)

cos(75°) = (√3 - 1) / (2√2)

Now, plug this value back into the dot product formula:

(a · b) = 15 * 4.6 * [(√3 - 1) / (2√2)]

(a · b) ≈ 15 * 4.6 * 0.366 = 26.01

So, the scalar product of vectors a and b is 26.01 units.

Now, let's find the magnitude of the vector product (axb). The magnitude of the vector product is given by:

|axb| = |a| * |b| * sin(θ)

We already have the values for |a| and |b| from the previous calculation. Now, we'll use sin(θ), where θ is 75°:

|axb| = 15 * 4.6 * sin(75°)

To find sin(75°), we can again use trigonometric identities:

sin(75°) = sin(45° + 30°)

Using the sum of angles formula for sine:

sin(45° + 30°) = sin(45°)cos(30°) + cos(45°)sin(30°)

sin(45°) and cos(45°) are both equal to 1/√2, and sin(30°) and cos(30°) are 1/2 and √3/2, respectively.

sin(75°) = (1/√2) * (1/2) + (1/√2) * (√3/2)

sin(75°) = (1/2√2) + (√3/2√2)

sin(75°) = (√3 + 1) / (2√2)

Now, calculate the magnitude of the vector product:

|axb| = 15 * 4.6 * [(√3 + 1) / (2√2)]

|axb| ≈ 15 * 4.6 * 0.933 = 64.59

So, the magnitude of the vector product axb is 64.59 units.

answered
User Maerch
by
7.9k points

Related questions