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Pleace help!!!!!!!!!!!!!
4x^2-64=8x-4

1 Answer

3 votes

Explanation:

Of course, I can help you with this equation. Let's solve for x:

4x^2 - 64 = 8x - 4

First, move all the terms to one side of the equation to set it equal to zero:

4x^2 - 8x - 64 + 4 = 0

Now, combine like terms:

4x^2 - 8x - 60 = 0

Next, divide the entire equation by 4 to simplify it:

x^2 - 2x - 15 = 0

Now, we have a quadratic equation in the form ax^2 + bx + c = 0, where a = 1, b = -2, and c = -15. To solve for x, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Plug in the values:

x = (-(-2) ± √((-2)² - 4(1)(-15))) / (2(1))

x = (2 ± √(4 + 60)) / 2

x = (2 ± √64) / 2

Now, simplify:

x = (2 ± 8) / 2

Now, we have two possible solutions:

x = (2 + 8) / 2 = 10 / 2 = 5

x = (2 - 8) / 2 = -6 / 2 = -3

So, the solutions to the equation are x = 5 and x = -3.

answered
User Sady
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