Question

When dilute sulphuric acid is added to barium chloride solution then what happens in a balanced equation?

Answer 1

H2SO4 + BaCl2 = BaSO4 + 2HCl

Step-by-step explanation:

Writing just the chemical compounds:

H2SO4 + BaCl2 = BaSO4 + HCl

Note that there are 2 Cl ions on the reactant side, but only 1 on the product side. So lets add a coefficient of 2 to the HCl product:

H2SO4 + BaCl2 = BaSO4 + 2HCl

This had the consequence of adding another H ion to the product side, but we are in luck: The reactant side contributes 2 H ions from the sulfuric acid, H2SO4. I wish the rest of life was that easy.

The other elements also balance:

Reactant Product

H 2 2

S 1 1

O 4 4

Ba 1 1

Cl 2 2

The balanced equation is:

H2SO4 + BaCl2 = BaSO4 + 2HCl